y=3(2)+2^2+6

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Solution for y=3(2)+2^2+6 equation: 



y=3(2)+2^2+6

We move all terms to the left:

y-(3(2)+2^2+6)=0

We add all the numbers together, and all the variables

y-42=0

We move all terms containing y to the left, all other terms to the right

y=42

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